推广型网站开发,网站反链接,安徽网站建设微信开发,保定网页设计招聘网站✨费纳姆密码#xff1a;加解密都需要密钥#xff0c;以二进制形式表示的密码。#xff08;密钥多是一次性的#xff0c;称位一次性密码本#xff09;
加密过程#xff1a;
char_num {A: 1000001, B: 1000010, C: 1000011, D: 1000100,E: 1000101, F: 1000110, G: 100…✨费纳姆密码加解密都需要密钥以二进制形式表示的密码。密钥多是一次性的称位一次性密码本
加密过程
char_num {A: 1000001, B: 1000010, C: 1000011, D: 1000100,E: 1000101, F: 1000110, G: 1000111, H: 1001000,I: 1001001, J: 1001010, K: 1001011, L: 1001100,M: 1001101, N: 1001110, O: 1001111, P: 1010000,Q: 1010001, R: 1010010, S: 1010011, T: 1010100,U: 1010101, V: 1010110, W: 1010111, X: 1011000,Y: 1011001, Z: 1011010}num_char {1000001: A, 1000010: B, 1000011: C, 1000100: D,1000101: E, 1000110: F, 1000111: G, 1001000: H,1001001: I, 1001010: J, 1001011: K, 1001100: L,1001101: M, 1001110: N, 1001111: O, 1010000: P,1010001: Q, 1010010: R, 1010011: S, 1010100: T,1010101: U, 1010110: V, 1010111: W, 1011000: X,1011001: Y, 1011010: Z, }# 转换
def txt_num(txt):txt txt.upper()result for i in txt:result result char_num[i]return result# 最终数字转换为字母
def num_list(txt):num 0s []while True:s.append(txt[num:num 7])num 7if num len(txt) - 7:breakreturn s# 加密 文本内容
def encipher(txt, k):result if txt.isalpha() and k.isalpha():txt txt_num(txt)k txt_num(k)j len(k)for i in range(0, len(txt)):if txt[i] k[i % j]:result 0else:result 1else:result 明文与密钥应为纯字母return result# 解密 文本为数字格式
def decipher(txt, k):result if k.isalpha():k txt_num(k)j len(k)for i in range(0, len(txt)):if txt[i] k[i % j]:result 0else:result 1result num_list(result)result_char for i in result:try:result_char result_char num_char[i]except KeyError:result_char result_char ?result result_charelse:result 密钥应为纯字母return resultif __name__ __main__:# 加解密,密文text,明文text_2text # 读文本文件key polartext_2 polarCTFprint(encipher(text_2, key))# print(decipher(text, key)) 解密过程
char_num {A: 1000001, B: 1000010, C: 1000011, D: 1000100,E: 1000101, F: 1000110, G: 1000111, H: 1001000,I: 1001001, J: 1001010, K: 1001011, L: 1001100,M: 1001101, N: 1001110, O: 1001111, P: 1010000,Q: 1010001, R: 1010010, S: 1010011, T: 1010100,U: 1010101, V: 1010110, W: 1010111, X: 1011000,Y: 1011001, Z: 1011010}num_char {1000001: A, 1000010: B, 1000011: C, 1000100: D,1000101: E, 1000110: F, 1000111: G, 1001000: H,1001001: I, 1001010: J, 1001011: K, 1001100: L,1001101: M, 1001110: N, 1001111: O, 1010000: P,1010001: Q, 1010010: R, 1010011: S, 1010100: T,1010101: U, 1010110: V, 1010111: W, 1011000: X,1011001: Y, 1011010: Z, }# 转换
def txt_num(txt):txt txt.upper()result for i in txt:result result char_num[i]return result# 最终数字转换为字母
def num_list(txt):num 0s []while True:s.append(txt[num:num 7])num 7if num len(txt) - 7:breakreturn s# 加密 文本内容
def encipher(txt, k):result if txt.isalpha() and k.isalpha():txt txt_num(txt)k txt_num(k)j len(k)for i in range(0, len(txt)):if txt[i] k[i % j]:result 0else:result 1else:result 明文与密钥应为纯字母return result# 解密 文本为数字格式
def decipher(txt, k):result if k.isalpha():k txt_num(k)j len(k)for i in range(0, len(txt)):if txt[i] k[i % j]:result 0else:result 1result num_list(result)result_char for i in result:try:result_char result_char num_char[i]except KeyError:result_char result_char ?result result_charelse:result 密钥应为纯字母return resultif __name__ __main__:# 加解密,密文text,明文text_2text 00000000000000000000000000000000000001001100110110001010# 读文本文件key polartext_2 polarCTF# print(encipher(text_2, key))print(decipher(text, key)) ✨杰弗逊转轮加密需要密钥并用很多行乱序英文字母表示密文的密码。首先要将密文按密钥顺序进行调整再根据密文顺序整每行字符串即可得到明文。
方法1 除了每行第一个字母组成的依次往后向下寻找有意义的字符串直到找到为止
方法2
import re
PasswordList
1: ZWAXJGDLUBVIQHKYPNTCRMOSFE
2: KPBELNACZDTRXMJQOYHGVSFUWI
3: BDMAIZVRNSJUWFHTEQGYXPLOCK
4: RPLNDVHGFCUKTEBSXQYIZMJWAO
5: IHFRLABEUOTSGJVDKCPMNZQWXY
6: AMKGHIWPNYCJBFZDRUSLOQXVET
7: GWTHSPYBXIZULVKMRAFDCEONJQ
8: NOZUTWDCVRJLXKISEFAPMYGHBQ
9: XPLTDSRFHENYVUBMCQWAOIKZGJ
10: UDNAJFBOWTGVRSCZQKELMXYIHP
11: MNBVCXZQWERTPOIUYALSKDJFHG
12: LVNCMXZPQOWEIURYTASBKJDFHG
13: JZQAWSXCDERFVBGTYHNUMKILOP ciphertext UOFJLBLSXJPJY # 存放密文
content re.findall(r(.*?), PasswordList, re.S) # 匹配所有的密码表字符串
key [2, 3, 7, 5, 13, 12, 9, 1, 8, 10, 4, 11, 6] # 密钥
list [] # 定义空列表list和空串ans
ans
for i in range(13):index content[key[i]-1].index(ciphertext[i])list.append((index))
for i in range(0, 26):flag for j in range(13):flag content[key[j]-1][(list[j]i) % 26]print(flag) 从出来的结果找出有意义的那串字符即为明文
✨常见图形密码—猪圈密码 变种形式1 变种形式2 ✨圣堂武士密码 ✨旗语密码 ✨盲文 ✨精灵语密码 ✨跳舞的人密码 ✨夏多密码下面的四个是方向指示符号向上右下左旋转碰到表示将密文整体进行该方向的旋转 ✨银河密码
