网站信息登记表扫描件,德勤管理咨询,深圳微信网站开发公司,阳城做网站直接怼代码#xff0c;刚好碰到了这种需求#xff0c;也是想了可久#xff0c;其实想想也还是挺简单的 public static void main(String[] args) { // 原始字符串集合 ListString originalList new ArrayList(); originalList.add(Hello); …直接怼代码刚好碰到了这种需求也是想了可久其实想想也还是挺简单的 public static void main(String[] args) { // 原始字符串集合 ListString originalList new ArrayList(); originalList.add(Hello); originalList.add(World); originalList.add(Android); originalList.add(Development); // 获取字符串的最大长度 int maxLength 0; for (String str : originalList) { maxLength Math.max(maxLength, str.length()); } // 使用循环和数组操作获取每个位置的字符集合 ListString charListAtIndex new ArrayList(); StringBuilder sb new StringBuilder(); for (int i 0; i maxLength; i) { charListAtIndex.clear(); for (String str : originalList) { if (i str.length()) { sb.setLength(0); // 清空 StringBuilder sb.append(str.charAt(i)); // 添加当前字符 charListAtIndex.add(sb.toString()); // 将 StringBuilder 转换为 String 并添加到列表中 } } System.out.println(Character List at Index i : charListAtIndex); } }
结果:
Character List at Index 0: [H, W, A, D]
Character List at Index 1: [e, o, n, e]
Character List at Index 2: [l, r, d, v]
Character List at Index 3: [l, o, o, l]
Character List at Index 4: [o, r, i, p]
Character List at Index 5: [m, e]
Character List at Index 6: [n, t]
