手机网站在线制作,淘宝客wordpress引流,注册网站代码,手机主题制作软件关联查询1对多返回
遇见的问题
审批主表#xff0c;和审批明细表#xff0c;一张审批对应多张明细数据#xff0c;每条明细数据的状态是不一样的#xff0c;现在需要根据明细的状态获取到主单子的状态#xff0c;状态返回矩阵如下
明细状态返回总状态都是已完成已完成都…关联查询1对多返回
遇见的问题
审批主表和审批明细表一张审批对应多张明细数据每条明细数据的状态是不一样的现在需要根据明细的状态获取到主单子的状态状态返回矩阵如下
明细状态返回总状态都是已完成已完成都是已终止已终止有进行中进行中有草稿草稿只有已完成和已终止已完成
观察报错
无
问题解决
SELECT vba.object_id,vba.create_time,vba.company_id,vba.approval_no,vba.finish_time,vba.business_table,vba.business_id,t2.enum_status,vba.create_user_name,vba.apply_abstract
FROM view_bus_approval vbaLEFT JOIN view_bus_payment vbp ON vba.object_id vbp.approval_idLEFT JOIN (SELECT ba.approval_id,CASEWHEN ba.enum_status 05AND ba.cnt 0 THEN05WHEN ba.enum_status 10AND ba.cnt 0 THEN10WHEN ba.enum_status 20AND ba.cnt ba1.cnt THEN20WHEN ba.enum_status 30AND ba.cnt ba1.cnt THEN30WHEN ba.enum_status 40AND ba.cnt ba1.cnt THEN40ELSE 20END AS enum_statusFROM (SELECT t2.approval_id,t2.enum_status,sum(cnt) AS cntFROM view_approval_detail_status_cnt t2WHERE t2.approval_user_id 1GROUP BY t2.approval_id,t2.enum_status) baLEFT JOIN (SELECT t2.approval_id, sum(cnt) AS cntFROM view_approval_detail_status_cnt t2WHERE t2.approval_user_id 1GROUP BY t2.approval_id) ba1 ON ba1.approval_id ba.approval_idGROUP BY ba.approval_id) t2 ON t2.approval_id vba.object_id
WHERE vba.is_deleted 0AND vba.business_table bus_official_seal_use
ORDER BY (CASEvba.enum_statusWHEN 05 THEN1WHEN 30 THEN2WHEN 10 THEN3WHEN 40 THEN4WHEN 20 THEN5ELSE 6END) ASC,vba.create_time DESC;这里用到了两层查询一遍是查询该申请单子的所有明细的数量
SELECT t2.approval_id, sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id 1
GROUP BY t2.approval_id然后外层是查询该单子下再按照状态进行分组求和
SELECT t2.approval_id,t2.enum_status,sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id 1
GROUP BY t2.approval_id,t2.enum_status然后拿到的申请单id再group by这个单子id因为一个单子只会返回一个状态就达到效果了。
结语
如果哪位大佬发现了解释的不对的还望不吝赐教。十分感谢
